To solve \( 27^{4/3} \), we can break it down as follows:
- First, find the cube root of 27, which is \( 3 \).
- Then raise that result to the power of 4:
\[ 27^{4/3} = (27^{1/3})^4 = 3^4 \]
Calculating \( 3^4 \):
\[ 3^4 = 3 \times 3 \times 3 \times 3 = 81 \]
Thus, \( 27^{4/3} = 81 \).
The correct response is 81.