Given that the cube root of 27 is 3, what is 27 4/3?(1 point)

Question

Responses

81
81

108
108

4
4

12

Answer 1

To solve \( 27^{4/3} \), we can break it down as follows:

1. First, find the cube root of 27, which is \( 3 \).
2. Then raise that result to the power of 4:

\[ 27^{4/3} = (27^{1/3})^4 = 3^4 \]

Calculating \( 3^4 \):

\[ 3^4 = 3 \times 3 \times 3 \times 3 = 81 \]

Thus, \( 27^{4/3} = 81 \).

The correct response is 81.