∫1/x dx from 1 to 2
= lnx | from 1 to 2
= ln2 - ln1
= ln2 , since ln1 = 0
Given that the antiderivative of f of x equals 1 divided by x is F(x) = Ln|x| + C, evaluate the integral from 1 to 2 of the 1 divided by x, dx.
ln3
1/2
-1/2
ln2
1 answer