Given that sinx= 3/5 and that x terminates in Quadrant 2 , determine the values for cosx and tanx

Question

Find Cos x/2

Answer 1

sin A = 3/5 = y/r, Q2.
x^2 + y^2 = r^2
x^2 = r^2 - y^2 = 5^2 - 3^2=25 - 9 = 16
X = -4, Q2.

Cos A = X/r = -4/5
Tan A = Y/X = 3/-4 = -3/4