P(x) = x³ - 13x + 12
Cubics are tough to solve, so assume there's some low-hanging fruit, root-wise.
P(1) = 0
P(x) = (x-1)(x² + x - 12)
I think you can make it from here, eh?
Given that P(x)=x(x^2-13) +12,express P(x)as a product of linear factors.
1 answer