The following OA , OB etc are vectors
OA + AB = OB
AB = OB - OA
AB = OB + AO
= (4,1,-3) + (-3,2,-1)
= (1,3,-4)
|AB| = √(1^2 + 3^2 + (-4)^2)
= √26
= appr 5.10
Given that OA = 3i – 2j + k and OB = 4i + j – 3k. Find the distance between point A and B to 2 decimal places.
2 answers
Amaizing