Given that log3=0.4771 and iog5=0.6990 evaluate the value of log1.35+log2.25

Answer 1

log1.35+log2.25
= log(135 * 10^-2) + log(225 * 10^-2)
= log135 - 2 + log225 - 2
= log(5*27) + log(9*25) - 4
= log5 + 3log3 + 2log3 - 2log5 - 4
= 5log3 - log5 - 4
...

Answer 2

given that log 3=0.4771 and log 5 =0.699 find long 135 without using calcukator or tables