Given that log y=log(10x^n).make n the subject of the formula

Question

oobleck · Accepted Answer

just recall that exponents and logs are inverse operations, like + and - or * and /. y = log(10x^n) 10^y = 10x^n x^n = 10^y/10 = 10^(y-1) x = 10^{^(y-1)/n}