(a) log(28) = log(7*2^2) = log(7) + 2*log(2) = 0.8451 + 2*0.3010 = 0.8451 + 0.602 = 1.4471
(b) log(0.0049) = log(7^-2) = -2*log(7) = -2*0.8451 = -1.6902
(c) antilog(3.3010) = 10^3.3010 = 2050.939
(d) antilog(-1.1549) = 10^(-1.1549) = 0.07672
Given that log(7) = 0.8451 and log(2) = 0.3010,
calculate the following: (a) log(28). (b) log(0.0049). (c) antilog(3.3010). (d) antilog(-1.1549).
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