log6=log2+log3
log108=log2+log27+log2
= 2log2 + 3log3
ploga=log2+log3
q loga=2log2+3log3
double the firstequation, then subtract.
(q-2p)loga=log3
log3/loga=q-2p
given that log(6)/log(a) = p and log(108)/log(a) = q , express log(3)/log(a) in terms of p and q
1 answer
1 answer