Given that:
H2 (g) + F2 (g) ---> 2HF (g) H(rxn)= -546.6 kJ
2H2 (g) + O2 (g) ---> 2H2O (l) H (rxn)= -571.6 kJ
calculate the value for H(run) for...
2F2(g) + 2H2O (l) ---> 4HF (g) + O2 (g)
_____kJ?
3 answers
What's H(run) mean?
Sorry i meant H(rxn) (of the reaction)
-521.6kJ