f'= 6x^5 * h + h'*x^6
you know x, h(x), and h'(x). compute.
Given that f(x)=x^6h(x)
h(-1)=3
h'(-1)=6
Calculate f'(-1).
3 answers
I'm lost how how they provide h(-1)=3 and h'(-1)=6
Would x=-1 and the h be 3, and h' be 6 in 6x^5 * h + h'*x^6 ? Or would the h be -1 and the h' be -1 and then I put the 3 and 6 outside the equation like 6x^5 * h + h'*x^6 =3+6?
Would x=-1 and the h be 3, and h' be 6 in 6x^5 * h + h'*x^6 ? Or would the h be -1 and the h' be -1 and then I put the 3 and 6 outside the equation like 6x^5 * h + h'*x^6 =3+6?
If h(-1) = 3 then f(-1) = (-1)^6 * h(-1) = (-1)^6 * 3
1 answer