Given that f(x)

is a one-to-one function and f(1)=−3
, f(5)=6
, and f(3)=5
, find f−1(5)
.

1 answer

To find \( f^{-1}(5) \), we start by interpreting the meaning of the notation \( f^{-1}(y) \). Specifically, \( f^{-1}(y) \) gives us the value of \( x \) such that \( f(x) = y \).

Given that \( f(3) = 5 \), we can conclude that:

\[ f^{-1}(5) = 3 \]

Thus, the answer is:

\[ \boxed{3} \]