Given that f(x) = 9x2−50,

apply the Remainder Theorem to find the remainder of (9x2−50)÷(x − 73).
(1 point)
Responses

-50
-50

-1
-1

-2033
- 203 thirds

-29

1 answer

To apply the Remainder Theorem, we need to evaluate the function \( f(x) = 9x^2 - 50 \) at \( x = 73 \). The Remainder Theorem states that the remainder of dividing a polynomial \( f(x) \) by \( x - c \) is equal to \( f(c) \).

Here, \( c = 73 \).

Now, let's calculate \( f(73) \):

\[ f(73) = 9(73)^2 - 50 \]

First, calculate \( 73^2 \):

\[ 73^2 = 5329 \]

Now, substitute back into the function:

\[ f(73) = 9(5329) - 50 \]

Calculating \( 9 \times 5329 \):

\[ 9 \times 5329 = 47961 \]

Now, subtract 50:

\[ f(73) = 47961 - 50 = 47911 \]

Thus, the remainder when \( 9x^2 - 50 \) is divided by \( x - 73 \) is:

\[ \boxed{47911} \]

Since none of the answer options provided appear to align with the calculated result, it seems that there may have been a misunderstanding or misprint in the choices given.