Let g(x) = f^-1(x)
If f(a) = b, g'(b) = 1/f'(a)
f(0) = 1, so
g'(1) = 1/f'(0) = 1/(2-sin(1))
Given that f(x)=2x+cos(x) is one-to-one. use the formula
(f^−1)′(x)=1 / f′(f^−1(x))
to find (f^−1)′(1)
(f^−1)′(1)=
1 answer
(f^−1)′(x)=1 / f′(f^−1(x))
to find (f^−1)′(1)
(f^−1)′(1)=
1 answer
1 answer
1 answer
1 answer
1 answer