Given that Antarctica is roughly semicircular with a radius of 2000 km and has an average ice thickness of 3000 m. a) How many km3 of ice does Antarctica contain? b) Assuming all the ice melts, how much will this raise sea level (ignoring that the Earth has curvature and density differences between water and ice)?

asked by bibi meeble

12 years ago

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1 answer

a. V = 0.5(pi*r^2)*h.
V=0.5(3.14*(2000)^2)*3=18,840,000 km^3.

answered by Henry

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Question

Given that Antarctica is roughly semicircular with a radius of 2000 km and has an average ice thickness of 3000 m. a) How many km3 of ice does Antarctica contain? b) Assuming all the ice melts, how much will this raise sea level (ignoring that the Earth has curvature and density differences between water and ice)?

1 answer

a. V = 0.5(pi*r^2)*h.
V=0.5(3.14*(2000)^2)*3=18,840,000 km^3.

Henry · Answer

a. V = 0.5(pi*r^2)*h. V=0.5(3.14*(2000)^2)*3=18,840,000 km^3.