Are sure that the equation is NOT
a√(b^2-c) = 5k ?
or else the way you have it, it would simply become
ab -c = 5k
So I will assume it is a√(b^2-c) = 5k
I will do the 2nd, you do the first
2.
a√(b^2-c) = 5k
4√49-c) = 55
√(49-c) = 55/4
square both sides
49-c = 3025/16
-c = 3025/16 - 49
-c = 2241/16
c = - 2241/16
Given that a√b^2-c = 5k, find the value of:
1. k when a = 3, b = 6 and c = 20
2. c when a = 4, b = 7, and k = 11
Explain your working please
4 answers
Is the formula correct? √b^2? That's just b
However, if you mean √(b^2-c) then just plug in the numbers!
5k = 3*√(36-20) = 3*4 = 12
not so hard, eh?
However, if you mean √(b^2-c) then just plug in the numbers!
5k = 3*√(36-20) = 3*4 = 12
not so hard, eh?
√b^2 = b
Therefore, the equation is really:
ab - c = 5k
Insert values and calculate.
Therefore, the equation is really:
ab - c = 5k
Insert values and calculate.
Very bad to finish