To solve this system of equations, we can use the method of substitution.
First, we solve the second equation for x:
3x - 8y = 5
3x = 8y + 5
x = (8y + 5)/3
Next, substitute x into the first equation:
9((8y + 5)/3)² - 64y² = 185
9(64y² + 80y + 25)/9 - 64y² = 185
64y² + 80y + 25 - 64y² = 185
80y + 25 = 185
80y = 160
y = 2
Now, substitute y back into the equation x = (8y + 5)/3:
x = (8(2) + 5)/3
x = (16 + 5)/3
x = 21/3
x = 7
Therefore, the product of x and y is:
x * y = 7 * 2 = 14
Given that 9x²-64y²=185 and 3x-8y=5, find the product of x and y
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