given that 9002.05 can be written as 9*10^3+2*10^a+5*10^b.are integers,find the value of a and b

Question

help me

Answer 1

9*10^3 = 9000
So after 9002.05 is reduced by 9000 , we are left with
2.005 or
2 + .005
= 2*10^0 + 5*10^-3

so 9002.005
= 9*10^3+2*10^a+5*10^b
= 9*10^3 + 2*10^0 + 5.0*10^-3

a=0 , b = -3