Given that 4,p,q,13 are consecutive terms of a a.p find the value of p and q

Answer 1

p-4 = q-p
q-p = 13-q

Now just solve for q and p

Or, note that there are two equally-spaced terms between 4 and 13. So, the difference (13-4) is divided into three equal parts. That should help.

Answer 2

First use this formula nth=a d(n-1)
13=4 d(4-1). 13=4 3d
13-4=3d. 3d/3=9/3
d=3
Secondly to find p and q use the formula for finding common difference( D )
Therefore d=2nd term-1st term
3=p-4. P=3 4=7
P=7
Since 3rd term=a 2d. q=a 2d. q=4 2(3)
q=4 6. q=10

Answer 3

Q=10

Answer 4

Please the formula was not stated very well to get the answer as somebody who is learning mathematics it will not be clear on u get ur answers.

Answer 5

Show me the complete workings

Answer 6

Still dont get it pls

Answer 7

First of all our it this way
p-4=q-p
q-p=q+13
Then collect like terms and solve simultaneously
Ur answer will be p=7, q=10