Given that 3x _5y_3=0 and 2y _ 6x + 5=0 find the value of x

Answer 1

To find the value of x, we need to solve the system of equations:

3x - 5y + 3 = 0 (equation 1)
2y - 6x + 5 = 0 (equation 2)

Let's solve the system of equations using the substitution method:

From equation 2, we can isolate y:

2y = 6x - 5
y = 3x - 5/2 (equation 3)

Now, substitute equation 3 into equation 1:

3x - 5(3x - 5/2) + 3 = 0
3x - 15x + 25/2 + 3 = 0
-12x + 25/2 + 3 = 0
-12x + 31/2 = 0

Now, isolate x:

-12x = -31/2
x = -31/2 / -12
x = 31/24
x = 1.29

Therefore, the value of x is approximately 1.29.