Given tanθ=−4/3, where π/2<θ<π, what is the value of 1/(sinθ+cosθ)?

Answer 1

Jason asked the same question a week ago
Here is my answer

http://www.jiskha.com/display.cgi?id=1364442848

Answer 2

Just noticed that in the previous question
it asked for 1/sinØ + cosØ
and I did
1/sinØ + cosØ
= 1/(4/5) + (-3/5)
= 5/4 - 3/5
= 13/20

You have changed it to 1/(sinØ + cosØ)
so it would be
1/(4/5 - 3/5)
= 1/(1/5)
= 5