Given sin(theta)=2/5, and theta is in Quadrant 2, find sin(2theta)
2 answers
The trig value is 2/5 and so is the other trig values in quadrant 2
In QII, cosθ < 0, so cosθ = -√21/5
And now recall that sin2θ = 2 sinθ cosθ
And now recall that sin2θ = 2 sinθ cosθ