Given sin= -√5/6 with π < u < 3π/2 and cos v= √3/5 with 0 < v < π/2 find sin(u-v) and tan(u+v). Please show work and simplify.

Answer 1

draw your angles in standard position. Recall that

sin = y/r
cos = x/r
tan = y/x

That means that:

sin u = -√5/6
cos u = -1/6
tan u = √5/1

sin v = √22/5
cos v = √3/5
tan v = √(22/3)

I may have misinterpreted the radicals if you were careless with parentheses. If so, fix them.

Now, just use your sum and difference formulas. If you get stuck, "Please show work and simplify."