second is from 90 to 180 degrees
r^2 = 100 cos^2 T
x^2 + y^2 = 100 [ x^2/(x^2+y^2) ]
(x^2 + y^2)^2 =100 x^2
x^4 + 2 x^2 y^2 + y^4 = 100 x^2
Given r = 10 cos θ
If you sketched an angle of θ = 150 degrees, what quadrant would it be located in?
It's either the first or second... I think second?
Multiply both sides of r = 10 cos θ by r. Transform the resulting equation into Cartesian coordinates.
2 answers
Thank you so much!