Point P partitions segment AB in a m:n ratio.
Use Section rormula.
If point P partitions AB in a m:n ratio, then the coordinates of point P are:
x coordinate = ( m ∙ x2 + n ∙ x1 ) / ( m + n )
y coordinate = ( m ∙ y2 + n ∙ y1 ) / ( m + n )
In this case:
x1 = 0 , x2 = 3 , y1 = 0 , y2 = 6 , m = 3 , n = 2
So:
x = ( m ∙ x2 + n ∙ x1 ) / ( m + n )
x = ( 3 ∙ 3 + 2 ∙ 0 ) / ( 3 + 2 )
x = 9 / 5
y = ( m ∙ y2 + n ∙ y1 ) / ( m + n )
y = ( 3 ∙ 6 + 2 ∙ 0 ) / ( 3 + 2 )
y = 18 / 5
P ( 9 / 5 , 18 / 5 )
Given points (0, 0) and (3, 6), find the point which partitions the segment into 3:2
Please explain?
1 answer