This is a limiting reagent problem BECAUSE BOTH reactants are given.
1. Calculate moles Mg. moles = g/molar mass.
2. Calculate moles HCl. moles = M x L
3. Using the coefficients in the balanced equation, determine how many moles of H2 will be produced by EACH reactant.
4. Choose the lower number of moles of H2, the reactant producing that number will be the limiting reagent, then multiply by 22.4 L/mol to determine the volume (then change to mL)
Given:
Mg + 2HCl --> H2 + MgCl2
0.250 g of magnesium reacts with 10.00 mL of 1.5 M HCl.
What volume (in mL) of H2 gas is produced?
1 answer
1 answer