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Given: M is the midpoint of LN . ∠LMP ≅ ∠NMO, ON⊥NM , PL⊥LM
Prove: ∆NMO ≅ ∆LMP
1 answer
∠LMP ≅ ∠NMO (given)
LM ≅ NM (since M is midpoint)
∠L ≅ ∠N (given: both ⊥)
so, ASA --> ≅
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