Given: M is the midpoint of LN . ∠LMP ≅ ∠NMO, ON⊥NM , PL⊥LM

Question

Prove: ∆NMO ≅ ∆LMP

Answer 1

∠LMP ≅ ∠NMO (given)
LM ≅ NM (since M is midpoint)
∠L ≅ ∠N (given: both ⊥)

so, ASA --> ≅