To evaluate \( \log_8 32 \) using a different base, we can use the change of base formula:
\[ \log_a b = \frac{\log_c b}{\log_c a} \]
where \( c \) is any positive integer base. A common and convenient choice for many logarithmic evaluations is base \( 2 \).
Using base \( 2 \):
\[ \log_8 32 = \frac{\log_2 32}{\log_2 8} \]
Now we need to calculate each logarithm separately:
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Calculate \( \log_2 32 \): \[ 32 = 2^5 \quad \text{therefore} \quad \log_2 32 = 5 \]
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Calculate \( \log_2 8 \): \[ 8 = 2^3 \quad \text{therefore} \quad \log_2 8 = 3 \]
Now we can substitute these values back into our equation:
\[ \log_8 32 = \frac{\log_2 32}{\log_2 8} = \frac{5}{3} \]
Thus, \( \log_8 32 = \frac{5}{3} \).