Given log8 32 , change the base to an integer other than 10 to easily evaluate the logarithm.(1 point) logx 32/logx 8= log8 32

Answer 1

To change the base of a logarithm, we can use the change of base formula:

log_a (b) = log_x (b) / log_x (a)

In this case, we want to change the base of log_8 (32) to an integer other than 10. Let's choose the base x.

log_8 (32) = log_x (32) / log_x (8)

Now, let's find the value of log_x (32) and log_x (8).

log_x (32) = log_x (2^5) = 5

log_x (8) = log_x (2^3) = 3

Now, substitute the values back into the formula:

log_8 (32) = 5 / 3

So, log_8 (32) with the base changed to an integer other than 10 is 5/3.