Given log4 ,( 32+x) =3 what is the value of ?

1 answer

To solve the equation \( \log_4(32 + x) = 3 \), we can rewrite it in its exponential form. The equation states that \( 32 + x \) is equal to \( 4^3 \).

Calculating \( 4^3 \):

\[ 4^3 = 64 \]

Now, we can set up the equation:

\[ 32 + x = 64 \]

To find \( x \), we subtract 32 from both sides:

\[ x = 64 - 32 \]

Calculating the right side:

\[ x = 32 \]

Thus, the value of \( x \) is \( \boxed{32} \).

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