Given l= 30 in w= 20 in h= 18 in and x= 36.1 in solve for d round the the nearest tenth

1 answer

To solve for \( d \), we first need to identify the relationship between the variables given. If the variables \( l \), \( w \), \( h \), and \( x \) are related through a specific formula or equation, please provide that context.

However, if we assume that \( d \) is derived from the dimensions (length \( l \), width \( w \), height \( h \)), we may be looking for a common measurement, like the diagonal of a rectangular prism formed by these dimensions.

The diagonal \( d \) of a rectangular prism can be calculated using the formula:

\[ d = \sqrt{l^2 + w^2 + h^2} \]

Substituting the given values:

  • \( l = 30, \text{in} \)
  • \( w = 20, \text{in} \)
  • \( h = 18, \text{in} \)

Calculating \( d \):

  1. Calculate \( l^2 \): \[ l^2 = 30^2 = 900 \]

  2. Calculate \( w^2 \): \[ w^2 = 20^2 = 400 \]

  3. Calculate \( h^2 \): \[ h^2 = 18^2 = 324 \]

  4. Now, sum these values: \[ l^2 + w^2 + h^2 = 900 + 400 + 324 = 1624 \]

  5. Finally, take the square root to find \( d \): \[ d = \sqrt{1624} \approx 40.31 \]

Rounding to the nearest tenth, we find: \[ d \approx 40.3, \text{in} \]

Thus, the rounded value of \( d \) is 40.3 in.