Given k(x)=−0.5x5(3x+1)2(1−4x) , find the multiplicity of (3x+1) and describe the behavior of the graph of k(x) at the associated x-intercept.(1 point) Responses The multiplicity of (3x+1) is 2. At the associated x-intercept, the graph of k(x) crosses the x-axis. The multiplicity of left parenthesis 3 x plus 1 right parenthesis is 2. At the associated x -intercept, the graph of k ( x ) crosses the x -axis. The multiplicity of (3x+1) is 2. At the associated x-intercept, the graph of k(x) touches the x-axis and turns around. The multiplicity of left parenthesis 3 x plus 1 right parenthesis is 2. At the associated x -intercept, the graph of k ( x ) touches the x -axis and turns around. The multiplicity of (3x+1) is −13 . At the associated x-intercept, the graph of k(x) crosses the x-axis. The multiplicity of left parenthesis 3 x plus 1 right parenthesis is negative Start Fraction 1 over 3 End Fraction . At the associated x -intercept, the graph of k ( x ) crosses the x -axis. The multiplicity of (3x+1) is −13 . At the associated x-intercept, the graph of k(x) touches the x-axis and turns around.

1 answer

To analyze the polynomial \( k(x) = -0.5x^5(3x+1)^2(1-4x) \), we will focus on the factor \( (3x+1) \).

  1. Finding the multiplicity of \( (3x+1) \): The factor \( (3x+1) \) appears in \( k(x) \) as \( (3x+1)^2 \). Therefore, the multiplicity of \( (3x+1) \) is 2.

  2. Describing the behavior of the graph at the associated x-intercept: When the multiplicity of a factor is even, the graph will touch the x-axis at the x-intercept corresponding to that factor and turn around (bounce off).

The x-intercept associated with \( (3x+1) \) is found by setting it to zero:

\[ 3x + 1 = 0 \quad \Rightarrow \quad 3x = -1 \quad \Rightarrow \quad x = -\frac{1}{3} \]

At this x-intercept \( x = -\frac{1}{3} \), since the multiplicity is even (specifically, 2), the graph of \( k(x) \) will touch the x-axis and turn around.

Final conclusion:

  • The multiplicity of \( (3x+1) \) is 2.
  • At the associated x-intercept, the graph of \( k(x) \) touches the x-axis and turns around.
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