given h(x)= cotx/x

Question

find h'(ð /2)

Answer 1

since h is a function of x, not sure what ð is. Maybe it's pi?

Anyway,

h'(x) = [-x csc^2(x) + cot(x)]/x^2

h'(pi/2) = [-pi/2 * 1 + 0]/(pi^2 / 4)
= - 2/pi