Given h(x)=3x2−2x+8 , find h(2) . show your work

Answer 1

To find h(2), we need to substitute x = 2 into the given function h(x):

h(2) = 3(2)^2 - 2(2) + 8
h(2) = 3(4) - 4 + 8
h(2) = 12 - 4 + 8
h(2) = 16

Therefore, h(2) = 16.