Given h(x)=3x2−2x+8ℎ(𝑥)=3𝑥2−2𝑥+8 , find h(2)ℎ(2) .Show all work and process to show how you solved the problem. You can upload a picture of your work on paper if you prefer.(2 points)

Answer 1

To find h(2), we need to plug in x=2 into the given function h(x)=3x^2-2x+8:

h(2) = 3(2)^2 - 2(2) + 8
h(2) = 3(4) - 4 + 8
h(2) = 12 - 4 + 8
h(2) = 16

Therefore, h(2) = 16.