Given g(x) = (x + 5)(x2 - 6x + 13), find the one real zero of g(x):
I think it's -5
Find the two complex zeros of g(x):
2 answers
*(x + 5)(x^2 - 6x + 13)
correct for real root x = -5
for complex:
x^2 - 6x + 13 = 0
x =(6 ± √-16)/2
= (6 ± 4i)/2
= 3 ± 2i
for complex:
x^2 - 6x + 13 = 0
x =(6 ± √-16)/2
= (6 ± 4i)/2
= 3 ± 2i