Given `g\left(x\right)=x^{2}-3x-10`, which statement is true?Given `g\left(x\right)=x^{2}-3x-10`, which statement is true?

1 answer

To analyze the function \( g(x) = x^2 - 3x - 10 \), we can look at various aspects such as the vertex, roots, or the nature of the function (e.g., whether it is increasing or decreasing).

  1. Finding the Roots: We can find the roots of the function by setting \( g(x) = 0 \):

    \[ x^2 - 3x - 10 = 0 \]

    We can factor this quadratic:

    \[ (x - 5)(x + 2) = 0 \]

    Thus, the roots are \( x = 5 \) and \( x = -2 \).

  2. Vertex: The vertex of a parabola in the form \( ax^2 + bx + c \) can be determined using the formula:

    \[ x = -\frac{b}{2a} \]

    In this case, \( a = 1 \) and \( b = -3 \):

    \[ x = -\frac{-3}{2 \cdot 1} = \frac{3}{2} \]

    To find the y-coordinate of the vertex, substitute \( x = \frac{3}{2} \) back into \( g(x) \):

    \[ g\left(\frac{3}{2}\right) = \left(\frac{3}{2}\right)^2 - 3\left(\frac{3}{2}\right) - 10 \] \[ = \frac{9}{4} - \frac{9}{2} - 10 = \frac{9}{4} - \frac{18}{4} - \frac{40}{4} = \frac{9 - 18 - 40}{4} = \frac{-49}{4} \]

    So the vertex is at \( \left(\frac{3}{2}, -\frac{49}{4}\right) \).

  3. Nature of the Function: Since the leading coefficient \( a = 1 \) is positive, the parabola opens upwards. This means:

    • The minimum value of the function occurs at the vertex.
    • The function decreases until it reaches \( x = \frac{3}{2} \) and then increases thereafter.
  4. Conclusion: Depending on the statements you have, here is what you can conclude:

    • The function has roots at \( x = 5 \) and \( x = -2 \).
    • The vertex of the parabola is at \( \left(\frac{3}{2}, -\frac{49}{4}\right) \), which represents a minimum point.
    • The function is decreasing on the interval \( (-\infty, \frac{3}{2}) \) and increasing on \( (\frac{3}{2}, \infty) \).

If you provide specific statements, I can help determine which one is true based on this analysis.

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