Given: G = 6.67259 × 10−11 Nm2/kg2

Question

Mimas, a moon of Saturn, has an orbital
radius of 1.8 × 108 m and an orbital period of
about 22.6 h.
Use Newton’s version of Kepler’s third law
and these data to find the ma

Answer 1

Your question is incomplete. Do you want the mass of Saturn?

If you are unfamiliar with the law in question, you can derive it by equating the gravity force to the centripetal force.

GmM/R^2 = mV^2/R = (m/R)*(2 pi R/P)^2

GM = 4 pi^2 *(R^3/P^2)

M is the mass of Saturn, P is the moon's period and R is the radius of the moon's orbit. the mass of Mimas (m) cancels out.

Solve for M