Given F(x)=-6/x-3 -1 1.for which values of x is f(x) undefined? 2.for which values of f will the function have real roots 3.what is the domain of f 4.calculate the x and y intercepts of f

Answer 1

F is undefined where the denominator is zero

#2 ?

#3 domain is all reals except for the undefined value(s)

#4
y-intercept (at x=0):
-6/(0-3) -1 = -6/-3 - 1 = 2-1 = 1

x-intercept (at y=0)
-6/(x-3)-1 = 0
-6 - (x-3) = 0
-6-x+3 = 0
x = -3