Given f(x)=4x2−10x−3

, according to the Remainder Theorem, f(2)
can be found by finding the remainder of which of the following division quotients?(1 point)
Responses

(4x2−10x−3)÷x
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by x

(4x2−10x−3)÷2
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by 2

(4x2−10x−3)÷(x+2)
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x plus 2 right parenthesis

(4x2−10x−3)÷(x−2)
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x minus 2 right parenthesis

1 answer

According to the Remainder Theorem, to find \( f(2) \) for the polynomial \( f(x) = 4x^2 - 10x - 3 \), you need to evaluate the polynomial at \( x = 2 \). Alternatively, \( f(2) \) can also be found as the remainder when dividing the polynomial \( f(x) \) by \( x - 2 \).

Therefore, the correct division quotient for finding \( f(2) \) is:

\[ (4x^2 - 10x - 3) \div (x - 2) \]

So the correct response from the options provided is:

\[ (4x^2 - 10x - 3) \div (x - 2) \]