Given f(x)=4x2−10x−3 , according to the Remainder Theorem, f(2) can be found by finding the remainder of which of the following division quotients?(1 point)

Question

Responses

(4x2−10x−3)÷x
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by x

(4x2−10x−3)÷(x−2)
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x minus 2 right parenthesis

(4x2−10x−3)÷2
left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by 2

(4x2−10x−3)÷(x+2)

Answer 1

According to the Remainder Theorem, the remainder of the polynomial \( f(x) \) when divided by \( x - c \) is equal to \( f(c) \).

To find \( f(2) \), we need to divide \( f(x) \) by \( x - 2 \).

Thus, the correct option is:

\[ (4x^2 - 10x - 3) \div (x - 2) \]

This division will give us the remainder \( f(2) \).