Given f″(x)=−4sin(2x) and f′(0)=3 and f(0)=−6.

Find f(π/6)

1 answer

f"(x) = -4sin(2x)
f'(x) = 2cos(2x) + c1
f(x) = sin(2x) + c1*x + c2

Now plug in the initial conditions to find c1 and c2
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