No arrows leaves me cold.
I can't translate some of the symbols.
Anyway, the answer to your problem is to add the oxidation volts to the reduction volts.
Given:
Cr3+(aq) + 3e¨C  Cr(s); E¡ã = ¨C0.74 V
Pb2+(aq) + 2e¨C  Pb(s); E¡ã = ¨C0.13 V
What is the standard cell potential for the following reaction?
2Cr(s) + 3Pb2+(aq) ¡ú 3Pb(s) + 2Cr3+(aq)
1 answer