Given circle P centered at the origin, with a radius of 4 units.

circle p is not a function
domain: -4 less than or equal to times less than or equal to 4
0->3
1->7
2->11
3->15
x^2+ y^2=16

1 answer

It seems you are referring to two different concepts: the first part discusses a circle centered at the origin with a radius of 4 units, while the second part appears to describe a mapping of integer values to specific outputs. Let's break this down.

Circle P:

The equation for a circle centered at the origin (0,0) with a radius of 4 units is given by:

\[ x^2 + y^2 = 16 \]

This is derived from the general formula for a circle \((x-h)^2 + (y-k)^2 = r^2\), where \( (h, k) \) is the center of the circle and \( r \) is the radius. In this case:

  • Center \((h,k) = (0,0)\)
  • Radius \(r = 4\) so \(r^2 = 16\)

The domain of the circle in the context of a vertical line test (to graph it) indicates that for every x in the range of -4 to 4, there are two corresponding y values (which confirms that the circle is not a function).

Mapping:

The second part of your query provides mappings from integers to specific outputs:

  • \(0 \to 3\)
  • \(1 \to 7\)
  • \(2 \to 11\)
  • \(3 \to 15\)

This seems to suggest a function where the input value is an integer, and the output is a corresponding value. A pattern can be observed within the outputs; it looks like the mapping could represent a linear relationship between the input (x) and output (y).

Indeed, the outputs follow the linear pattern, which can be analyzed as follows:

  1. Finding the pattern:
    • From 0 to 3: \(3 - 0 = 3\)
    • From 1 to 7: \(7 - 3 = 4\)
    • From 2 to 11: \(11 - 7 = 4\)
    • From 3 to 15: \(15 - 11 = 4\)

If we look closely, the output increases by 4 for the last three values. It's useful to express the output explicitly in a formula.

  1. Finding a linear equation: You might notice that for every incremental increase of 1 in x after x=0, we increase the output by 4. Therefore, a potential formula might look like:

\[ f(x) = 4x + 3 \]

Verifying with your points:

  • For \(x = 0\): \(f(0) = 4(0) + 3 = 3\)
  • For \(x = 1\): \(f(1) = 4(1) + 3 = 7\)
  • For \(x = 2\): \(f(2) = 4(2) + 3 = 11\)
  • For \(x = 3\): \(f(3) = 4(3) + 3 = 15\)

Conclusion:

You have a circle defined by \(x^2 + y^2 = 16\) and a mapping of integers to outputs defined by the function \(f(x) = 4x + 3\) for \(x = 0, 1, 2, 3\). Keep in mind that the circle is not a function due to the vertical line test, while the mapping you've identified does represent a valid function over the specified domain.