huh? a^1 = 1 and a^-1 = 1/a, so
4 = ba
16 = b/a
now divide:
4/16 = ba/(b/a)
1/4 = a^2
a = 1/2
so, b=8
f(x) = 8*2^-x
Given an exponential graph that are concave up and the points (1,4) and (-1, 16), give a possible formula of the function.
I plugged the variables into the f(x)=b times a^x and got:
4= b times a^1 and
16=b times a^-1
I am not sure where to go from here.
2 answers
Thank you! I forgot that you could divide the two!