this is a 30-60-90 triangle
m∠L = 30 °
... AK is the side opposite
AL (the hypotenuse) is twice AK
KL is AK times √3
the area is 1/2 the product of the two perpendicular sides
Given: ∆AKL, AK = 9
m∠K = 90o
m∠A = 60 °
Find: The perimeter of ∆AKL
The area of ∆AKL
1/ AK perpendicular to LK
2/AL is the third side
plz add answer and solution
1 answer