Given: ∆AKL, AK = 9

m∠K = 90o
m∠A = 60 °
Find: The perimeter of ∆AKL
The area of ∆AKL

1/ AK perpendicular to LK
2/AL is the third side

plz add answer and solution

1 answer

this is a 30-60-90 triangle

m∠L = 30 °
... AK is the side opposite

AL (the hypotenuse) is twice AK

KL is AK times √3

the area is 1/2 the product of the two perpendicular sides