Given: ABCD is a rectangle, diagnoals AC and BD intersect at E

Prove: Triangle AEB is isosceles

3 answers

In a previous question you probably proved that in a rectangle the two diagonals are equal and bisect each other, making all 4 smaller segments equal to each other.
Now prove triangles AED and CEB congruent and each is isosceles, and from that angle DAE = angle CBE
therefore their complements are equal.
therefore the base angles of triangle ABE are equal making it isosceles.

Write it up using the method and procedure that your teacher or the course requires.
find the measure of <2
find the measure of <4 and round your answer to the nearest tenth