Sketch is the big thing!!
On mine , I extended AC to M so that angle BMC = 60°
Also you can see that angle MCB = 60° (external angle)
So triangle CBM is equilater, and since CM = 12
CB = MB = 12
Also, since ABC is isosceles and CA = CB
CA = 12
now by the sine law:
AB/sin120° = 12/sin30
AB = ...
Given: ∆ABC is isosceles
m∠ACB = 120°
m∠BMC = 60°
CM = 12
Find: AB
can you guys help I'm really struggling with proofs (statement and reasons)
1 answer