angles BAE and DEA are alternate interior angles, so m∠DEA=70°.
AD=AE, so ∆DAE is isosceles. That means m∠ADE=70°.
m∠DAE is thus 180-70-70 = 40°
Given:
__
AB
∥
__
DE
m∠BAE=70°, AD=AE.
Find: m∠DAE.
Sorry if format is terrifiying or broken.
1 answer