Given a right triangle whose side lengths are integral multiples of 7, how many units are in the smallest possible perimeter

Answer 1

The smallest possible perimeter is obtained when we have the smallest possible sides.
But the sides are supposed to be multiples of 7
So they have to be 7 and 14
Hypotenuse^2 = 7^2 + 14^2
Hypotenuse = √245

so smallest possible perimter = 7+14+√245
= 21 + √245

Answer 2

21 + [(square root of 5) x 7]